Identifying Java Version from Registry.

Hi All,

OS: Win 7 64bit

OE: 10.2B SP 8 32bit

 

I'm trying to determine which version of java is installed from the registry with the following code.

 

DEFINE VARIABLE op-version AS CHARACTER   NO-UNDO.

LOAD "SOFTWARE\Wow6432Node\JavaSoft" BASE-KEY "HKEY_LOCAL_MACHINE" .

USE "SOFTWARE\Wow6432Node\JavaSoft" .

      

GET-KEY-VALUE SECTION "Java Runtime Environment" KEY "CurrentVersion" VALUE op-version.

 

MESSAGE "Paul Mowat - wow64/32" op-version VIEW-AS ALERT-BOX.

 

UNLOAD "SOFTWARE\Wow6432Node\JavaSoft".

 

LOAD "SOFTWARE\JavaSoft" BASE-KEY "HKEY_LOCAL_MACHINE" .

USE "SOFTWARE\JavaSoft" .

      

GET-KEY-VALUE SECTION "Java Runtime Environment" KEY "CurrentVersion" VALUE op-version.

 

MESSAGE "Paul Mowat - 64bit" op-version

VIEW-AS ALERT-BOX.

 

UNLOAD "SOFTWARE\JavaSoft".

 

I have both 64bit and 32bit versions installed.

 

HKLM

|

-> SOFTWARE

                |

                |-> JavaSoft

                                |-> Java Runtime Environment

                                                |-> CurrentVersion = 1.8

                |

                |-> Wow6432Node

                                |-> Java Runtime Environment

                                                |-> CurrentVersion = 1.7

 

I expect the first check to get the 32bit version and the second to get the 64bit version. What is happening though is that they are both finding the value 1.7 that is held against SOFTWARE\Wow6432Node\JavaSoft.

 

My intention is to check for the 32bit version and if not installed drop down to the 64bit version.

 

Anyone have any ideas?

 

Thanks

 

Paul